Use properties of logarithms to show that log(3) + log(4) + log(5) − log(6) = 1

Answer:⇒ ( log(3) + log(4) ) + log(5) − log(6)or⇒ log(3 × 4) + log(5) - log(6)or⇒ log(12) + log(5) - log(6)or⇒ log(12 × 5) - log(6)or⇒ log(60) - log(6)or⇒ [tex]\log(\frac{60}{6})[/tex]or⇒ log(10)also,log(10) = 1Step-by-step explanation:Given equation; log(3) + log(4) + log(5) − log(6) = 1now, we know the property of log function as:1) log(A) + log(B) = log(AB)and,2) log(A) - log(B) = [tex]\log(\frac{A}{B})[/tex]therefore, applying the property (1) on the LHS⇒ ( log(3) + log(4) ) + log(5) − log(6)or⇒ log(3 × 4) + log(5) - log(6)or⇒ log(12) + log(5) - log(6)again applying the property (1)⇒ log(12 × 5) - log(6)or⇒ log(60) - log(6)now applying the property 2, we get⇒ [tex]\log(\frac{60}{6})[/tex]or⇒ log(10)also,log(10) = 1Hence,LHS = 1 = RHSHence, proved